The force we must apply to an object in order for it to completely deform is known as stress. Furthermore, although we are aware of human stress, it can be challenging to comprehend stress in physics. Additionally, we will talk about stress, the Stress Formula, its derivation, and a solved example in this topic. Stress Formula will be simpler for students to understand by the end of this article.
How objects react?
You fold a piece of paper to make an origami crane. Additionally, even after the paper has been relieved, the finished origami maintains the new shape. On the other hand, a rubber band that has been stretched will snap back when released. In addition, some objects retain a portion of their original shape when stretched. Additionally, some objects change shape when forces are applied to them, but even when we apply the same amount of force to all objects, they all change in different ways.
There are a few ideas that must be examined first before discussing stress. In addition, stress is defined as the force (strength or energy) applied to an object divided by the cross-sectional area of the object.
Additionally, larger objects can withstand greater forces. Additionally, by substituting stress for force, we can use the same yield stress for the same material, regardless of the actual size of the object.
Most importantly, stress and strain are inversely correlated; as one rises, the other follows suit. Additionally, an object will deform more and more under stress until it breaks.
In addition, all objects initially deform elastically, but when the stress on the object exceeds a certain level, it begins to deform plastically. At this point, the object has reached its yield stress.
Additionally, despite the fact that each portion’s size may vary, stress and strain always bond in materials. The elastic deformation is also linear. Additionally, the materials an object is made of affect the slope line. Furthermore, plastic deformation is not linear, which makes modelling it more challenging.
Students can thoroughly practise and deepen their understanding of Stress Formula by using the practise problems on the Extramarks website. Students are better able to solve practise problems using the Stress Formula. Students can achieve excellent exam results if they thoroughly and frequently practise the Stress Formula practise questions. On the Extramarks website, students can find assistance in a number of ways. By registering on the website, students can access the Stress Formula, which will aid in their understanding of the chapter.
Derivation of the Stress Formula
With the presence of Extramarks, students now have access to an excellent platform for all of their academic needs. They are one of the most trustworthy sources for the Stress Formula because all of the content on the website was written by their subject-matter experts. The most knowledgeable specialists, or subject-matter experts, create the best Stress Formula. Students should be required to complete the Stress Formula practise problems. The sample issues are available to students. It can be very advantageous for students who are accurately listed. The Stress Formula curriculum is comparatively interesting and instructive. Students must learn a vast amount of information to master the chapter. The goal of Extramarks’ website is to make learning simpler.
Solved Example on Stress Formula
For making the Stress Formula more clear to students, let’s consider some examples that will help students in understanding them better.
Find the stress of an object on which the acting force is 50 Newtons (N) and the cross-section area is 5 mm2?
Let’s write down what is given in the question
Force or F = 50 N (Newtons)
Cross-section area or A = 5 mm2
Now let’s put values given in the question in the formula
σ = FA
σ = 50N5×10−6
σ = 10×106Nm2
So, the stress on the object is 10×106Nm2.