Surface Tension Formula
Surface Tension Formula
Understanding the formula is a critical component of comprehending the topic of Surface Tension Formula. The formula is a component of the formula’s application. It is an important topic for students who want to pursue engineering or medicine in the future. The Extramarks platform includes a variety of audio and video modules that extend learning beyond textbooks. Students who prefer to learn by reading can consult the chapter plans for topics such as Surface Tension Formula. This Surface Tension Formula is important to understand and remember because it may be tested.
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The Surface Tension Formula contains a number of textbook questions that aid in student comprehension. These questions are frequently asked in exams. However, these issues may not be fully addressed in class. It is still necessary for students to understand the concepts of the Surface Tension Formula through textbook questions. Surface Tension Formula textbook solutions are available on the Extramarks website and mobile app. These solutions cover all textbook questions while also providing additional questions for students to practise. These questions are found in school exams and may also appear in competitive exams. For many students, the competitive examinations are career-defining. As a result, it is critical that they practise regularly.
Definition
Surface tension is the attractive force found in liquids that pulls surface molecules into the rest of the liquid. It also reduces the surface area. The attractive forces we’re discussing here are caused by electrostatic forces.
This cohesion is usually referred to at the gas-liquid interface; remember, not liquid-solid or liquid-liquid. You may have noticed it frequently in water, but it also occurs to some extent in all other liquids.
Furthermore, we can see electrostatic forces. These forces pull molecules together. The slight dipole with water is capable of attracting molecules specifically to each other. As a result, it is able to produce a tight-knit cohesive unit.
When in a liquid state, the force has little effect because each molecule pulls in all directions towards the other molecules. However, because there are no molecules to pull the others up, these molecules do not pull up at all on the liquid’s surface.
A strong force between the molecules pulls them down. As a result, it forms a solid barrier at the liquid-gas interface. As a result, breaking through the liquid’s surface will require much more force than going through liquid.
The textbook solutions Surface Tension Formula for are available on the Extramarks website and mobile app. These solutions cover all textbook questions while also providing additional questions for students to practise. These questions are found in school exams and may also appear in competitive exams. For many students, the competitive examinations are career-defining. As a result, it is critical that they practise these questions thoroughly prior to any examinations.
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Formula
Surface tension is defined as the ratio of the surface force F acting on a liquid to the length d along which the force acts. This is the same thing that allows insects like water striders to walk on water or a paperclip to float. As a result, the surface tension formula is:
Surface tension = (surface force)/ (length force acts)
γ = F /d
Over here:
Γ refers to the Surface tension
F is the force which applies to the liquid
d refers to the length where the force acts
Solved Examples on Surface Tension
Question- You have a small piece of metal that is 1 cm long and weighs 0.1 N. Find out the surface tension.
Answer- Looking at the figures, we see that we have the F as 0.1 N and d as 1 cm. We can find out the surface tension by applying the above formula:
γ = F/d
γ = 0.1N/1 cm
0.1 N/ 0.01
m = 10 N/m.
Therefore, the surface tension is 10 N/m.
Question- A small insect of about 1.5 cm long is posed upon the water. The surface tension of the water is 5 N/m. Calculate the estimated mass of the insect?
Answer- Looking at the figures, we have our γ as 5 N/m and d as 1.5 cm. We can find out the force, which is the weight, from the surface tension. Thus, we have:
F = γ d
F = 5 N/m 1.5 cm
F= 5 N/m 0.015 m
F= 0.075 N
Further, the mass of the insect will be given by:
M = F/g
Over here, g = 9.8 m/s2 which is the acceleration of gravity.
Finally,
M = 0.075 N / 9.8 m/s2 = 0.0076 Kg = 7.6 grams
Therefore, the mass of the insect on the water is 7.6 grams.
