Temperature Formula
Temperature Formula
The Temperature Formula is crucial, and it talks about a number of things. It is a new concept that is introduced to students in higher classes of the school curriculum. Not all students might be prepared for this level of complexity, and it might also intimidate a number of students. The topic and the subject have nothing to be intimidated of. It is simple and students can learn about it in their textbooks.
Recommended textbooks are the primary source of learning for students, Every education board has different recommendations of textbooks. Students rely heavily on these textbooks to understand the chapters and prepare for examinations. The Temperature Formula can be learned by the students with the help of these textbooks. The textbooks have multiple questions within and at the end of the chapter to test the understanding of the students. The questions related to Temperature Formula can seem challenging to students, as there are no step-wise solutions provided. Students might look into multiple sources to find the textbook solutions for the questions from Temperature Formula.
There are multiple platforms online providing textbook solutions for Temperature Formula, but not all of them are reliable. Learning about the Temperature Formula from unreliable sources can lead to wrong information. Students can rely on the study guides available on the Extramarks platform.
The Extramarks platform covers complex topics like Temperature Formula with simplicity and in an easy-to-understand language. These study guides cover all the aspects of the topics such as Temperature Formula to prepare students for the examinations. The textbook solutions are available along with extra questions and sample papers. Students can have a holistic learning experience and also learn with their classmates. The Extramarks platform covers all subjects in all classes of the school curriculum. Therefore, students from any education board can learn about topics like Temperature Formula.
Example 1
Determine the temperature if 200 J of heat is released by the body of mass 6 Kg and has a specific heat of 0.8 J/KgoC .
Solution:
Given:
Heat released Q = 200 J,
Mass m = 6 Kg,
Specific Heat c = 0.8 J/KgoC
The temperature is given by ΔT = Q / mc
= 200 / 6 x 0.8
ΔT= 41.66oC .
Example 2
Determine the heat released when the temperature changes by 40oC by a body of mass 3 Kg which has a specific heat of 0.7 J/kgoC .
Solution:
Given:
Temperature change = 40oC ,
Mass m = 3 kg,
Specific heat c = 0.7 J/kgoC ,
The Heat released is given by formula Q = mc ΔT
= 3 × 0.7 × 40
Q = 84 J
