Terminal Velocity Formula

Terminal Velocity Formula

Physics can be a challenging subject. It is introduced to students around the middle school, but advances during the course of education. The subject introduces students to multiple topics and chapters like the Terminal Velocity Formula. Physics consist of multiple formulas, and it is important for the students to understand these concepts. The Terminal Velocity Formula is important because it helps students in later classes and even in higher education.

Students can learn about Terminal Velocity Formula in detail on the Extramarks platform. The topic, along with other topics, has been explained in detail and helps students in having a clarity of understanding. Before solving the questions related to the Terminal Velocity Formula, students need to understand everything about it.

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Terminal Velocity

Terminal velocity is the highest velocity that can be attained by an object when it falls through the air. It happens when the sum of the dragged force (Fd) and buoyancy is equal to the downward force of gravity (FG) acting on the body. The object holds zero acceleration since the net force acting is zero.

Terminal Velocity Formula is given as

Terminal velocity formula


g = acceleration due to gravity,

h = height from the ground

Terminal velocity formula is applied to calculate terminal velocity, acceleration due to gravity or height if any of these quantities are known.

Terminal velocity is expressed in meter per second (m/s).

Solved Examples

Example 1

A man is at the height of 2000 m from the ground. What would be his terminal velocity?



Height h = 2000 m,

The terminal velocity formula is given by

V= √2×9.8 ×2000

= √39200

= 197.98 m/s.

Example 2

Determine the height of the body if its terminal velocity is 100 m/s.



Terminal velocity ,V= 100 m/s

The height is given by

terminal velocity formula 1

= 10000 / 9.8 x 2

h = 510.204 m.

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